Integrand size = 17, antiderivative size = 191 \[ \int \frac {\left (a+c x^2\right )^p}{(d+e x)^2} \, dx=\frac {x \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p} \operatorname {AppellF1}\left (\frac {1}{2},-p,2,\frac {3}{2},-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d^2}+\frac {e^2 x^3 \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p} \operatorname {AppellF1}\left (\frac {3}{2},-p,2,\frac {5}{2},-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{3 d^4}-\frac {c d e \left (a+c x^2\right )^{1+p} \operatorname {Hypergeometric2F1}\left (2,1+p,2+p,\frac {e^2 \left (a+c x^2\right )}{c d^2+a e^2}\right )}{\left (c d^2+a e^2\right )^2 (1+p)} \]
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Time = 0.11 (sec) , antiderivative size = 191, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.412, Rules used = {771, 441, 440, 455, 70, 525, 524} \[ \int \frac {\left (a+c x^2\right )^p}{(d+e x)^2} \, dx=\frac {x \left (a+c x^2\right )^p \left (\frac {c x^2}{a}+1\right )^{-p} \operatorname {AppellF1}\left (\frac {1}{2},-p,2,\frac {3}{2},-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d^2}+\frac {e^2 x^3 \left (a+c x^2\right )^p \left (\frac {c x^2}{a}+1\right )^{-p} \operatorname {AppellF1}\left (\frac {3}{2},-p,2,\frac {5}{2},-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{3 d^4}-\frac {c d e \left (a+c x^2\right )^{p+1} \operatorname {Hypergeometric2F1}\left (2,p+1,p+2,\frac {e^2 \left (c x^2+a\right )}{c d^2+a e^2}\right )}{(p+1) \left (a e^2+c d^2\right )^2} \]
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Rule 70
Rule 440
Rule 441
Rule 455
Rule 524
Rule 525
Rule 771
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {d^2 \left (a+c x^2\right )^p}{\left (d^2-e^2 x^2\right )^2}-\frac {2 d e x \left (a+c x^2\right )^p}{\left (d^2-e^2 x^2\right )^2}+\frac {e^2 x^2 \left (a+c x^2\right )^p}{\left (-d^2+e^2 x^2\right )^2}\right ) \, dx \\ & = d^2 \int \frac {\left (a+c x^2\right )^p}{\left (d^2-e^2 x^2\right )^2} \, dx-(2 d e) \int \frac {x \left (a+c x^2\right )^p}{\left (d^2-e^2 x^2\right )^2} \, dx+e^2 \int \frac {x^2 \left (a+c x^2\right )^p}{\left (-d^2+e^2 x^2\right )^2} \, dx \\ & = -\left ((d e) \text {Subst}\left (\int \frac {(a+c x)^p}{\left (d^2-e^2 x\right )^2} \, dx,x,x^2\right )\right )+\left (d^2 \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p}\right ) \int \frac {\left (1+\frac {c x^2}{a}\right )^p}{\left (d^2-e^2 x^2\right )^2} \, dx+\left (e^2 \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p}\right ) \int \frac {x^2 \left (1+\frac {c x^2}{a}\right )^p}{\left (-d^2+e^2 x^2\right )^2} \, dx \\ & = \frac {x \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p} F_1\left (\frac {1}{2};-p,2;\frac {3}{2};-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d^2}+\frac {e^2 x^3 \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p} F_1\left (\frac {3}{2};-p,2;\frac {5}{2};-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{3 d^4}-\frac {c d e \left (a+c x^2\right )^{1+p} \, _2F_1\left (2,1+p;2+p;\frac {e^2 \left (a+c x^2\right )}{c d^2+a e^2}\right )}{\left (c d^2+a e^2\right )^2 (1+p)} \\ \end{align*}
Time = 0.32 (sec) , antiderivative size = 141, normalized size of antiderivative = 0.74 \[ \int \frac {\left (a+c x^2\right )^p}{(d+e x)^2} \, dx=\frac {\left (\frac {e \left (-\sqrt {-\frac {a}{c}}+x\right )}{d+e x}\right )^{-p} \left (\frac {e \left (\sqrt {-\frac {a}{c}}+x\right )}{d+e x}\right )^{-p} \left (a+c x^2\right )^p \operatorname {AppellF1}\left (1-2 p,-p,-p,2-2 p,\frac {d-\sqrt {-\frac {a}{c}} e}{d+e x},\frac {d+\sqrt {-\frac {a}{c}} e}{d+e x}\right )}{e (-1+2 p) (d+e x)} \]
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\[\int \frac {\left (c \,x^{2}+a \right )^{p}}{\left (e x +d \right )^{2}}d x\]
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\[ \int \frac {\left (a+c x^2\right )^p}{(d+e x)^2} \, dx=\int { \frac {{\left (c x^{2} + a\right )}^{p}}{{\left (e x + d\right )}^{2}} \,d x } \]
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\[ \int \frac {\left (a+c x^2\right )^p}{(d+e x)^2} \, dx=\int \frac {\left (a + c x^{2}\right )^{p}}{\left (d + e x\right )^{2}}\, dx \]
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\[ \int \frac {\left (a+c x^2\right )^p}{(d+e x)^2} \, dx=\int { \frac {{\left (c x^{2} + a\right )}^{p}}{{\left (e x + d\right )}^{2}} \,d x } \]
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\[ \int \frac {\left (a+c x^2\right )^p}{(d+e x)^2} \, dx=\int { \frac {{\left (c x^{2} + a\right )}^{p}}{{\left (e x + d\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {\left (a+c x^2\right )^p}{(d+e x)^2} \, dx=\int \frac {{\left (c\,x^2+a\right )}^p}{{\left (d+e\,x\right )}^2} \,d x \]
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